7x+1=3(4x-5)+16

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Solution for 7x+1=3(4x-5)+16 equation: 



7x+1=3(4x-5)+16

We move all terms to the left:

7x+1-(3(4x-5)+16)=0



We calculate terms in parentheses: -(3(4x-5)+16), so:

3(4x-5)+16

We multiply parentheses

12x-15+16

We add all the numbers together, and all the variables

12x+1

Back to the equation:

-(12x+1)



We get rid of parentheses

7x-12x-1+1=0

We add all the numbers together, and all the variables

-5x=0

x=0/-5

x=0

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