7x+2(2x+10)=108

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Solution for 7x+2(2x+10)=108 equation: 



7x+2(2x+10)=108

We move all terms to the left:

7x+2(2x+10)-(108)=0

We multiply parentheses

7x+4x+20-108=0

We add all the numbers together, and all the variables

11x-88=0

We move all terms containing x to the left, all other terms to the right

11x=88

x=88/11

x=8

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