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7x+2(3x+5)=2(6x-4)+x
We move all terms to the left:
7x+2(3x+5)-(2(6x-4)+x)=0
We multiply parentheses
7x+6x-(2(6x-4)+x)+10=0
We calculate terms in parentheses: -(2(6x-4)+x), so:We add all the numbers together, and all the variables
2(6x-4)+x
We add all the numbers together, and all the variables
x+2(6x-4)
We multiply parentheses
x+12x-8
We add all the numbers together, and all the variables
13x-8
Back to the equation:
-(13x-8)
13x-(13x-8)+10=0
We get rid of parentheses
13x-13x+8+10=0
We add all the numbers together, and all the variables
18!=0
There is no solution for this equation
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