7x+2(4x-2)=27

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Solution for 7x+2(4x-2)=27 equation: 



7x+2(4x-2)=27

We move all terms to the left:

7x+2(4x-2)-(27)=0

We multiply parentheses

7x+8x-4-27=0

We add all the numbers together, and all the variables

15x-31=0

We move all terms containing x to the left, all other terms to the right

15x=31

x=31/15

x=2+1/15

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