7x+2(6x-12)=128

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Solution for 7x+2(6x-12)=128 equation: 



7x+2(6x-12)=128

We move all terms to the left:

7x+2(6x-12)-(128)=0

We multiply parentheses

7x+12x-24-128=0

We add all the numbers together, and all the variables

19x-152=0

We move all terms containing x to the left, all other terms to the right

19x=152

x=152/19

x=8

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