7x+2(x+2)=8x+-2(x+-1)

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Solution for 7x+2(x+2)=8x+-2(x+-1) equation: 



7x+2(x+2)=8x+-2(x+-1)

We move all terms to the left:

7x+2(x+2)-(8x+-2(x+-1))=0

We add all the numbers together, and all the variables

7x+2(x+2)-(8x+-2(x-1))=0

We use the square of the difference formula

7x+2(x+2)-(8x-2(x-1))=0

We multiply parentheses

7x+2x-(8x-2(x-1))+4=0



We calculate terms in parentheses: -(8x-2(x-1)), so:

8x-2(x-1)

We multiply parentheses

8x-2x+2

We add all the numbers together, and all the variables

6x+2

Back to the equation:

-(6x+2)



We add all the numbers together, and all the variables

9x-(6x+2)+4=0

We get rid of parentheses

9x-6x-2+4=0

We add all the numbers together, and all the variables

3x+2=0

We move all terms containing x to the left, all other terms to the right

3x=-2

x=-2/3

x=-2/3

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