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7x+2(x-4)=-3x-4-4x-8
We move all terms to the left:
7x+2(x-4)-(-3x-4-4x-8)=0
We add all the numbers together, and all the variables
7x+2(x-4)-(-7x-12)=0
We multiply parentheses
7x+2x-(-7x-12)-8=0
We get rid of parentheses
7x+2x+7x+12-8=0
We add all the numbers together, and all the variables
16x+4=0
We move all terms containing x to the left, all other terms to the right
16x=-4
x=-4/16
x=-1/4
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