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7x+2-5x=2(x-4)+3x
We move all terms to the left:
7x+2-5x-(2(x-4)+3x)=0
We add all the numbers together, and all the variables
2x-(2(x-4)+3x)+2=0
We calculate terms in parentheses: -(2(x-4)+3x), so:We get rid of parentheses
2(x-4)+3x
We add all the numbers together, and all the variables
3x+2(x-4)
We multiply parentheses
3x+2x-8
We add all the numbers together, and all the variables
5x-8
Back to the equation:
-(5x-8)
2x-5x+8+2=0
We add all the numbers together, and all the variables
-3x+10=0
We move all terms containing x to the left, all other terms to the right
-3x=-10
x=-10/-3
x=3+1/3
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