7x+2-5x=2(x-4)+3x

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Solution for 7x+2-5x=2(x-4)+3x equation: 



7x+2-5x=2(x-4)+3x

We move all terms to the left:

7x+2-5x-(2(x-4)+3x)=0

We add all the numbers together, and all the variables

2x-(2(x-4)+3x)+2=0



We calculate terms in parentheses: -(2(x-4)+3x), so:

2(x-4)+3x

We add all the numbers together, and all the variables

3x+2(x-4)

We multiply parentheses

3x+2x-8

We add all the numbers together, and all the variables

5x-8

Back to the equation:

-(5x-8)



We get rid of parentheses

2x-5x+8+2=0

We add all the numbers together, and all the variables

-3x+10=0

We move all terms containing x to the left, all other terms to the right

-3x=-10

x=-10/-3

x=3+1/3

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