7x+3(-x-3)=41

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Solution for 7x+3(-x-3)=41 equation: 



7x+3(-x-3)=41

We move all terms to the left:

7x+3(-x-3)-(41)=0

We add all the numbers together, and all the variables

7x+3(-1x-3)-41=0

We multiply parentheses

7x-3x-9-41=0

We add all the numbers together, and all the variables

4x-50=0

We move all terms containing x to the left, all other terms to the right

4x=50

x=50/4

x=12+1/2

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