7x+3(2x-2)=6(1+x)

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Solution for 7x+3(2x-2)=6(1+x) equation: 



7x+3(2x-2)=6(1+x)

We move all terms to the left:

7x+3(2x-2)-(6(1+x))=0

We add all the numbers together, and all the variables

7x+3(2x-2)-(6(x+1))=0

We multiply parentheses

7x+6x-(6(x+1))-6=0



We calculate terms in parentheses: -(6(x+1)), so:

6(x+1)

We multiply parentheses

6x+6

Back to the equation:

-(6x+6)



We add all the numbers together, and all the variables

13x-(6x+6)-6=0

We get rid of parentheses

13x-6x-6-6=0

We add all the numbers together, and all the variables

7x-12=0

We move all terms containing x to the left, all other terms to the right

7x=12

x=12/7

x=1+5/7

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