7x+3(4x-3)=109

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Solution for 7x+3(4x-3)=109 equation: 



7x+3(4x-3)=109

We move all terms to the left:

7x+3(4x-3)-(109)=0

We multiply parentheses

7x+12x-9-109=0

We add all the numbers together, and all the variables

19x-118=0

We move all terms containing x to the left, all other terms to the right

19x=118

x=118/19

x=6+4/19

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