7x+3(x-2)=4(x+1)-3

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Solution for 7x+3(x-2)=4(x+1)-3 equation: 



7x+3(x-2)=4(x+1)-3

We move all terms to the left:

7x+3(x-2)-(4(x+1)-3)=0

We multiply parentheses

7x+3x-(4(x+1)-3)-6=0



We calculate terms in parentheses: -(4(x+1)-3), so:

4(x+1)-3

We multiply parentheses

4x+4-3

We add all the numbers together, and all the variables

4x+1

Back to the equation:

-(4x+1)



We add all the numbers together, and all the variables

10x-(4x+1)-6=0

We get rid of parentheses

10x-4x-1-6=0

We add all the numbers together, and all the variables

6x-7=0

We move all terms containing x to the left, all other terms to the right

6x=7

x=7/6

x=1+1/6

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