7x+3(x-4)=10(2x+1)-2

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Solution for 7x+3(x-4)=10(2x+1)-2 equation: 



7x+3(x-4)=10(2x+1)-2

We move all terms to the left:

7x+3(x-4)-(10(2x+1)-2)=0

We multiply parentheses

7x+3x-(10(2x+1)-2)-12=0



We calculate terms in parentheses: -(10(2x+1)-2), so:

10(2x+1)-2

We multiply parentheses

20x+10-2

We add all the numbers together, and all the variables

20x+8

Back to the equation:

-(20x+8)



We add all the numbers together, and all the variables

10x-(20x+8)-12=0

We get rid of parentheses

10x-20x-8-12=0

We add all the numbers together, and all the variables

-10x-20=0

We move all terms containing x to the left, all other terms to the right

-10x=20

x=20/-10

x=-2

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