7x+3-(x-2)=10x(2-3)-5

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Solution for 7x+3-(x-2)=10x(2-3)-5 equation: 



7x+3-(x-2)=10x(2-3)-5

We move all terms to the left:

7x+3-(x-2)-(10x(2-3)-5)=0

We add all the numbers together, and all the variables

7x-(x-2)-(10x(-1)-5)+3=0

We get rid of parentheses

7x-x-(10x(-1)-5)+2+3=0



We calculate terms in parentheses: -(10x(-1)-5), so:

10x(-1)-5

We multiply parentheses

-10x-5

Back to the equation:

-(-10x-5)



We add all the numbers together, and all the variables

6x-(-10x-5)+5=0

We get rid of parentheses

6x+10x+5+5=0

We add all the numbers together, and all the variables

16x+10=0

We move all terms containing x to the left, all other terms to the right

16x=-10

x=-10/16

x=-5/8

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