7x+3x=-8(6x-12)-12(x+8)

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Solution for 7x+3x=-8(6x-12)-12(x+8) equation: 



7x+3x=-8(6x-12)-12(x+8)

We move all terms to the left:

7x+3x-(-8(6x-12)-12(x+8))=0

We add all the numbers together, and all the variables

10x-(-8(6x-12)-12(x+8))=0



We calculate terms in parentheses: -(-8(6x-12)-12(x+8)), so:

-8(6x-12)-12(x+8)

We multiply parentheses

-48x-12x+96-96

We add all the numbers together, and all the variables

-60x

Back to the equation:

-(-60x)



We get rid of parentheses

10x+60x=0

We add all the numbers together, and all the variables

70x=0

x=0/70

x=0

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