7x+4(3-x)+4-2(2-x)=5(3x+2)+8x-10

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Solution for 7x+4(3-x)+4-2(2-x)=5(3x+2)+8x-10 equation: 



7x+4(3-x)+4-2(2-x)=5(3x+2)+8x-10

We move all terms to the left:

7x+4(3-x)+4-2(2-x)-(5(3x+2)+8x-10)=0

We add all the numbers together, and all the variables

7x+4(-1x+3)-2(-1x+2)-(5(3x+2)+8x-10)+4=0

We multiply parentheses

7x-4x+2x-(5(3x+2)+8x-10)+12-4+4=0



We calculate terms in parentheses: -(5(3x+2)+8x-10), so:

5(3x+2)+8x-10

We add all the numbers together, and all the variables

8x+5(3x+2)-10

We multiply parentheses

8x+15x+10-10

We add all the numbers together, and all the variables

23x

Back to the equation:

-(23x)



We add all the numbers together, and all the variables

-18x+12=0

We move all terms containing x to the left, all other terms to the right

-18x=-12

x=-12/-18

x=2/3

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