7x+4(3x-11)=70

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Solution for 7x+4(3x-11)=70 equation: 



7x+4(3x-11)=70

We move all terms to the left:

7x+4(3x-11)-(70)=0

We multiply parentheses

7x+12x-44-70=0

We add all the numbers together, and all the variables

19x-114=0

We move all terms containing x to the left, all other terms to the right

19x=114

x=114/19

x=6

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