7x+4(4x-3)=4(6x+4)-17

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Solution for 7x+4(4x-3)=4(6x+4)-17 equation: 



7x+4(4x-3)=4(6x+4)-17

We move all terms to the left:

7x+4(4x-3)-(4(6x+4)-17)=0

We multiply parentheses

7x+16x-(4(6x+4)-17)-12=0



We calculate terms in parentheses: -(4(6x+4)-17), so:

4(6x+4)-17

We multiply parentheses

24x+16-17

We add all the numbers together, and all the variables

24x-1

Back to the equation:

-(24x-1)



We add all the numbers together, and all the variables

23x-(24x-1)-12=0

We get rid of parentheses

23x-24x+1-12=0

We add all the numbers together, and all the variables

-1x-11=0

We move all terms containing x to the left, all other terms to the right

-x=11

x=11/-1

x=-11

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