7x+4+2(x-5)=8(x+1)

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Solution for 7x+4+2(x-5)=8(x+1) equation: 



7x+4+2(x-5)=8(x+1)

We move all terms to the left:

7x+4+2(x-5)-(8(x+1))=0

We multiply parentheses

7x+2x-(8(x+1))-10+4=0



We calculate terms in parentheses: -(8(x+1)), so:

8(x+1)

We multiply parentheses

8x+8

Back to the equation:

-(8x+8)



We add all the numbers together, and all the variables

9x-(8x+8)-6=0

We get rid of parentheses

9x-8x-8-6=0

We add all the numbers together, and all the variables

x-14=0

We move all terms containing x to the left, all other terms to the right

x=14

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