7x+40=3x+4(7-2x)

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Solution for 7x+40=3x+4(7-2x) equation: 



7x+40=3x+4(7-2x)

We move all terms to the left:

7x+40-(3x+4(7-2x))=0

We add all the numbers together, and all the variables

7x-(3x+4(-2x+7))+40=0



We calculate terms in parentheses: -(3x+4(-2x+7)), so:

3x+4(-2x+7)

We multiply parentheses

3x-8x+28

We add all the numbers together, and all the variables

-5x+28

Back to the equation:

-(-5x+28)



We get rid of parentheses

7x+5x-28+40=0

We add all the numbers together, and all the variables

12x+12=0

We move all terms containing x to the left, all other terms to the right

12x=-12

x=-12/12

x=-1

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