7x+41=3(x+3)

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Solution for 7x+41=3(x+3) equation: 



7x+41=3(x+3)

We move all terms to the left:

7x+41-(3(x+3))=0



We calculate terms in parentheses: -(3(x+3)), so:

3(x+3)

We multiply parentheses

3x+9

Back to the equation:

-(3x+9)



We get rid of parentheses

7x-3x-9+41=0

We add all the numbers together, and all the variables

4x+32=0

We move all terms containing x to the left, all other terms to the right

4x=-32

x=-32/4

x=-8

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