7x+41=3(x+3)

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Solution for 7x+41=3(x+3) equation:



7x+41=3(x+3)
We move all terms to the left:
7x+41-(3(x+3))=0
We calculate terms in parentheses: -(3(x+3)), so:
3(x+3)
We multiply parentheses
3x+9
Back to the equation:
-(3x+9)
We get rid of parentheses
7x-3x-9+41=0
We add all the numbers together, and all the variables
4x+32=0
We move all terms containing x to the left, all other terms to the right
4x=-32
x=-32/4
x=-8

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