7x+4x-32=80-5x

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Solution for 7x+4x-32=80-5x equation:



7x+4x-32=80-5x
We move all terms to the left:
7x+4x-32-(80-5x)=0
We add all the numbers together, and all the variables
7x+4x-(-5x+80)-32=0
We add all the numbers together, and all the variables
11x-(-5x+80)-32=0
We get rid of parentheses
11x+5x-80-32=0
We add all the numbers together, and all the variables
16x-112=0
We move all terms containing x to the left, all other terms to the right
16x=112
x=112/16
x=7

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