7x+4x-32=80-5x

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Solution for 7x+4x-32=80-5x equation: 



7x+4x-32=80-5x

We move all terms to the left:

7x+4x-32-(80-5x)=0

We add all the numbers together, and all the variables

7x+4x-(-5x+80)-32=0

We add all the numbers together, and all the variables

11x-(-5x+80)-32=0

We get rid of parentheses

11x+5x-80-32=0

We add all the numbers together, and all the variables

16x-112=0

We move all terms containing x to the left, all other terms to the right

16x=112

x=112/16

x=7

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