7x+5(3-2x)=28

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Solution for 7x+5(3-2x)=28 equation: 



7x+5(3-2x)=28

We move all terms to the left:

7x+5(3-2x)-(28)=0

We add all the numbers together, and all the variables

7x+5(-2x+3)-28=0

We multiply parentheses

7x-10x+15-28=0

We add all the numbers together, and all the variables

-3x-13=0

We move all terms containing x to the left, all other terms to the right

-3x=13

x=13/-3

x=-4+1/3

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