7x+5-4x=4-4(x+12)

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Solution for 7x+5-4x=4-4(x+12) equation: 



7x+5-4x=4-4(x+12)

We move all terms to the left:

7x+5-4x-(4-4(x+12))=0

We add all the numbers together, and all the variables

3x-(4-4(x+12))+5=0



We calculate terms in parentheses: -(4-4(x+12)), so:

4-4(x+12)

determiningTheFunctionDomain
-4(x+12)+4

We multiply parentheses

-4x-48+4

We add all the numbers together, and all the variables

-4x-44

Back to the equation:

-(-4x-44)



We get rid of parentheses

3x+4x+44+5=0

We add all the numbers together, and all the variables

7x+49=0

We move all terms containing x to the left, all other terms to the right

7x=-49

x=-49/7

x=-7

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