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7x+5/7=8x^2/7+
We move all terms to the left:
7x+5/7-(8x^2/7+)=0
We get rid of parentheses
-8x^2/7+7x-+5/7=0
We multiply all the terms by the denominator
-8x^2+7x*7+5-()*7=0
We add all the numbers together, and all the variables
-8x^2+7x*7=0
Wy multiply elements
-8x^2+49x=0
a = -8; b = 49; c = 0;
Δ = b2-4ac
Δ = 492-4·(-8)·0
Δ = 2401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2401}=49$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(49)-49}{2*-8}=\frac{-98}{-16} =6+1/8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(49)+49}{2*-8}=\frac{0}{-16} =0 $
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