7x+5=3(x-4)+1

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Solution for 7x+5=3(x-4)+1 equation: 



7x+5=3(x-4)+1

We move all terms to the left:

7x+5-(3(x-4)+1)=0



We calculate terms in parentheses: -(3(x-4)+1), so:

3(x-4)+1

We multiply parentheses

3x-12+1

We add all the numbers together, and all the variables

3x-11

Back to the equation:

-(3x-11)



We get rid of parentheses

7x-3x+11+5=0

We add all the numbers together, and all the variables

4x+16=0

We move all terms containing x to the left, all other terms to the right

4x=-16

x=-16/4

x=-4

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