7x+5x-48=80-4x

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Solution for 7x+5x-48=80-4x equation: 



7x+5x-48=80-4x

We move all terms to the left:

7x+5x-48-(80-4x)=0

We add all the numbers together, and all the variables

7x+5x-(-4x+80)-48=0

We add all the numbers together, and all the variables

12x-(-4x+80)-48=0

We get rid of parentheses

12x+4x-80-48=0

We add all the numbers together, and all the variables

16x-128=0

We move all terms containing x to the left, all other terms to the right

16x=128

x=128/16

x=8

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