7x+6(x+1)=13(x+1)-7

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Solution for 7x+6(x+1)=13(x+1)-7 equation: 



7x+6(x+1)=13(x+1)-7

We move all terms to the left:

7x+6(x+1)-(13(x+1)-7)=0

We multiply parentheses

7x+6x-(13(x+1)-7)+6=0



We calculate terms in parentheses: -(13(x+1)-7), so:

13(x+1)-7

We multiply parentheses

13x+13-7

We add all the numbers together, and all the variables

13x+6

Back to the equation:

-(13x+6)



We add all the numbers together, and all the variables

13x-(13x+6)+6=0

We get rid of parentheses

13x-13x-6+6=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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