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7x+7/9x+9=0
Domain of the equation: 9x!=0We multiply all the terms by the denominator
x!=0/9
x!=0
x∈R
7x*9x+9*9x+7=0
Wy multiply elements
63x^2+81x+7=0
a = 63; b = 81; c = +7;
Δ = b2-4ac
Δ = 812-4·63·7
Δ = 4797
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4797}=\sqrt{9*533}=\sqrt{9}*\sqrt{533}=3\sqrt{533}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(81)-3\sqrt{533}}{2*63}=\frac{-81-3\sqrt{533}}{126} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(81)+3\sqrt{533}}{2*63}=\frac{-81+3\sqrt{533}}{126} $
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