7x+7=(3x-9)/4

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Solution for 7x+7=(3x-9)/4 equation: 



7x+7=(3x-9)/4

We move all terms to the left:

7x+7-((3x-9)/4)=0

We multiply all the terms by the denominator


7x*4)-((3x-9)+7*4)=0

We add all the numbers together, and all the variables

7x*4)-((3x-9)=0

Wy multiply elements

28x^2=0

a = 28; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·28·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{56}=0$

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