7x+8(x+(1/4))=3(6x-9)-8

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Solution for 7x+8(x+(1/4))=3(6x-9)-8 equation: 



7x+8(x+(1/4))=3(6x-9)-8

We move all terms to the left:

7x+8(x+(1/4))-(3(6x-9)-8)=0

We add all the numbers together, and all the variables

7x+8(x+(+1/4))-(3(6x-9)-8)=0

We multiply all the terms by the denominator


7x*4))+8(x+(-((3(6x-9)-8))*4))+1=0

Wy multiply elements

28x^2-((3(6x-9)-8))*4))+1=0

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