7x+8(x+1)=3(2x+4)+5

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Solution for 7x+8(x+1)=3(2x+4)+5 equation: 



7x+8(x+1)=3(2x+4)+5

We move all terms to the left:

7x+8(x+1)-(3(2x+4)+5)=0

We multiply parentheses

7x+8x-(3(2x+4)+5)+8=0



We calculate terms in parentheses: -(3(2x+4)+5), so:

3(2x+4)+5

We multiply parentheses

6x+12+5

We add all the numbers together, and all the variables

6x+17

Back to the equation:

-(6x+17)



We add all the numbers together, and all the variables

15x-(6x+17)+8=0

We get rid of parentheses

15x-6x-17+8=0

We add all the numbers together, and all the variables

9x-9=0

We move all terms containing x to the left, all other terms to the right

9x=9

x=9/9

x=1

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