7x+8(x+1/4=3(6x-9)-8

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Solution for 7x+8(x+1/4=3(6x-9)-8 equation: 



7x+8(x+1/4=3(6x-9)-8

We move all terms to the left:

7x+8(x+1/4-(3(6x-9)-8)=0



Domain of the equation: 4-(3(6x-9)-8)!=0

We move all terms containing x to the left, all other terms to the right

-(3(6x-9)-8)!=-4

x∈R



We multiply all the terms by the denominator


7x*4-(3(6x-9)-8)+8(x+1=0



We calculate terms in parentheses: -(3(6x-9)-8), so:

3(6x-9)-8

We multiply parentheses

18x-27-8

We add all the numbers together, and all the variables

18x-35

Back to the equation:

-(18x-35)



Wy multiply elements

28x-(18x-35)+8(x+1=0

We get rid of parentheses

28x-18x+8(x+1+35=0

We add all the numbers together, and all the variables

10x+8(x+1+35=0

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