7x+8(x1/4)=3(6x-9)-8

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Solution for 7x+8(x1/4)=3(6x-9)-8 equation: 


x in (-oo:+oo)

7*x+8*((x^1)/4) = 3*(6*x-9)-8 // - 3*(6*x-9)-8

7*x-(3*(6*x-9))+8*((x^1)/4)+8 = 0

7*x-3*(6*x-9)+8*(x/4)+8 = 0

7*x-3*(6*x-9)+2*x+8 = 0

7*x-3*(6*x-9)+2*x+8 = 0

2*x-11*x+8+27 = 0

8-9*x+27 = 0

35-9*x = 0

35-9*x = 0

35-9*x = 0 // - 35

-9*x = -35 // : -9

x = -35/(-9)

x = 35/9

x = 35/9

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