7x+8x+40=4(2x+5)-1

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Solution for 7x+8x+40=4(2x+5)-1 equation: 



7x+8x+40=4(2x+5)-1

We move all terms to the left:

7x+8x+40-(4(2x+5)-1)=0

We add all the numbers together, and all the variables

15x-(4(2x+5)-1)+40=0



We calculate terms in parentheses: -(4(2x+5)-1), so:

4(2x+5)-1

We multiply parentheses

8x+20-1

We add all the numbers together, and all the variables

8x+19

Back to the equation:

-(8x+19)



We get rid of parentheses

15x-8x-19+40=0

We add all the numbers together, and all the variables

7x+21=0

We move all terms containing x to the left, all other terms to the right

7x=-21

x=-21/7

x=-3

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