7x-(-3x)+7=3(x-4)+20

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Solution for 7x-(-3x)+7=3(x-4)+20 equation: 



7x-(-3x)+7=3(x-4)+20

We move all terms to the left:

7x-(-3x)+7-(3(x-4)+20)=0

We get rid of parentheses

7x+3x-(3(x-4)+20)+7=0



We calculate terms in parentheses: -(3(x-4)+20), so:

3(x-4)+20

We multiply parentheses

3x-12+20

We add all the numbers together, and all the variables

3x+8

Back to the equation:

-(3x+8)



We add all the numbers together, and all the variables

10x-(3x+8)+7=0

We get rid of parentheses

10x-3x-8+7=0

We add all the numbers together, and all the variables

7x-1=0

We move all terms containing x to the left, all other terms to the right

7x=1

x=1/7

x=1/7

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