7x-(12-(3x-4))=5x-(-(2x-2)-3)

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Solution for 7x-(12-(3x-4))=5x-(-(2x-2)-3) equation: 



7x-(12-(3x-4))=5x-(-(2x-2)-3)

We move all terms to the left:

7x-(12-(3x-4))-(5x-(-(2x-2)-3))=0



We calculate terms in parentheses: -(12-(3x-4)), so:

12-(3x-4)

determiningTheFunctionDomain
-(3x-4)+12

We get rid of parentheses

-3x+4+12

We add all the numbers together, and all the variables

-3x+16

Back to the equation:

-(-3x+16)





We calculate terms in parentheses: -(5x-(-(2x-2)-3)), so:

5x-(-(2x-2)-3)



We calculate terms in parentheses: -(-(2x-2)-3), so:

-(2x-2)-3

We get rid of parentheses

-2x+2-3

We add all the numbers together, and all the variables

-2x-1

Back to the equation:

-(-2x-1)



We get rid of parentheses

5x+2x+1

We add all the numbers together, and all the variables

7x+1

Back to the equation:

-(7x+1)



We get rid of parentheses

7x+3x-7x-16-1=0

We add all the numbers together, and all the variables

3x-17=0

We move all terms containing x to the left, all other terms to the right

3x=17

x=17/3

x=5+2/3

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