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7x-(25x^2+12x)=
We move all terms to the left:
7x-(25x^2+12x)-()=0
We add all the numbers together, and all the variables
7x-(25x^2+12x)=0
We get rid of parentheses
-25x^2+7x-12x=0
We add all the numbers together, and all the variables
-25x^2-5x=0
a = -25; b = -5; c = 0;
Δ = b2-4ac
Δ = -52-4·(-25)·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-5}{2*-25}=\frac{0}{-50} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+5}{2*-25}=\frac{10}{-50} =-1/5 $
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