7x-(2x+5)=6(2+3x)-31

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Solution for 7x-(2x+5)=6(2+3x)-31 equation: 



7x-(2x+5)=6(2+3x)-31

We move all terms to the left:

7x-(2x+5)-(6(2+3x)-31)=0

We add all the numbers together, and all the variables

7x-(2x+5)-(6(3x+2)-31)=0

We get rid of parentheses

7x-2x-(6(3x+2)-31)-5=0



We calculate terms in parentheses: -(6(3x+2)-31), so:

6(3x+2)-31

We multiply parentheses

18x+12-31

We add all the numbers together, and all the variables

18x-19

Back to the equation:

-(18x-19)



We add all the numbers together, and all the variables

5x-(18x-19)-5=0

We get rid of parentheses

5x-18x+19-5=0

We add all the numbers together, and all the variables

-13x+14=0

We move all terms containing x to the left, all other terms to the right

-13x=-14

x=-14/-13

x=1+1/13

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