7x-(3+4x)=-x+(4-x)

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Solution for 7x-(3+4x)=-x+(4-x) equation: 



7x-(3+4x)=-x+(4-x)

We move all terms to the left:

7x-(3+4x)-(-x+(4-x))=0

We add all the numbers together, and all the variables

7x-(4x+3)-(-x+(-1x+4))=0

We get rid of parentheses

7x-4x-(-x+(-1x+4))-3=0



We calculate terms in parentheses: -(-x+(-1x+4)), so:

-x+(-1x+4)

We add all the numbers together, and all the variables

-1x+(-1x+4)

We get rid of parentheses

-1x-1x+4

We add all the numbers together, and all the variables

-2x+4

Back to the equation:

-(-2x+4)



We add all the numbers together, and all the variables

3x-(-2x+4)-3=0

We get rid of parentheses

3x+2x-4-3=0

We add all the numbers together, and all the variables

5x-7=0

We move all terms containing x to the left, all other terms to the right

5x=7

x=7/5

x=1+2/5

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