7x-(3x+4)=2(2x-1)+10

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Solution for 7x-(3x+4)=2(2x-1)+10 equation:


Simplifying
7x + -1(3x + 4) = 2(2x + -1) + 10

Reorder the terms:
7x + -1(4 + 3x) = 2(2x + -1) + 10
7x + (4 * -1 + 3x * -1) = 2(2x + -1) + 10
7x + (-4 + -3x) = 2(2x + -1) + 10

Reorder the terms:
-4 + 7x + -3x = 2(2x + -1) + 10

Combine like terms: 7x + -3x = 4x
-4 + 4x = 2(2x + -1) + 10

Reorder the terms:
-4 + 4x = 2(-1 + 2x) + 10
-4 + 4x = (-1 * 2 + 2x * 2) + 10
-4 + 4x = (-2 + 4x) + 10

Reorder the terms:
-4 + 4x = -2 + 10 + 4x

Combine like terms: -2 + 10 = 8
-4 + 4x = 8 + 4x

Add '-4x' to each side of the equation.
-4 + 4x + -4x = 8 + 4x + -4x

Combine like terms: 4x + -4x = 0
-4 + 0 = 8 + 4x + -4x
-4 = 8 + 4x + -4x

Combine like terms: 4x + -4x = 0
-4 = 8 + 0
-4 = 8

Solving
-4 = 8

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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