7x-(3x+5)-8=1/2(8x+20(-7x+5

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Solution for 7x-(3x+5)-8=1/2(8x+20(-7x+5 equation: 



7x-(3x+5)-8=1/2(8x+20(-7x+5

We move all terms to the left:

7x-(3x+5)-8-(1/2(8x+20(-7x+5)=0



Domain of the equation: 2(8x+20(-7x+5)-8!=0

x∈R



We get rid of parentheses

7x-3x-(1/2(8x+20(-7x+5)-8-5=0

We multiply all the terms by the denominator


7x*2(8x+20(-7x+5)-8-5-3x*2(8x+20(-7x+5)-8-5-(1=0

Wy multiply elements

28x^3(8=0

We do not support expression: x^3(8

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