7x-(3x+5)-8=1/2(8x+20)-7+5

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Solution for 7x-(3x+5)-8=1/2(8x+20)-7+5 equation: 



7x-(3x+5)-8=1/2(8x+20)-7+5

We move all terms to the left:

7x-(3x+5)-8-(1/2(8x+20)-7+5)=0



Domain of the equation: 2(8x+20)-7+5)!=0

We move all terms containing x to the left, all other terms to the right

2(8x+20)+5)!=7

x∈R



We get rid of parentheses

7x-3x-(1/2(8x+20)-7+5)-5-8=0

We multiply all the terms by the denominator


7x*2(8x+20)+5)-3x*2(8x+20)-7+5)-(1-5*2(8x+20)-7+5)-8*2(8x+20)-7+5)-7=0

Wy multiply elements

14x^2(8+5)-3x*2(8x+20)-5*2(8x+20)+5)-8*2(8x-7-7+5)-(1+20)-7+5)-7=0

We add all the numbers together, and all the variables

14x^213-3x*2(8x+20)-5*2(8x+20)+5)-8*2(8x-9)-21-7+5)-7=0

We add all the numbers together, and all the variables

14x^213-3x*2(8x+20)-5*2(8x+20)+5)-8*2(8x=0

Wy multiply elements

14x^213-6x^2(8-10x(8+5)-8*2(8x=0

We do not support expression: x^213

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