7x-(3x+5)-8=1/2(8x+20)-7x+5x

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Solution for 7x-(3x+5)-8=1/2(8x+20)-7x+5x equation:



7x-(3x+5)-8=1/2(8x+20)-7x+5x
We move all terms to the left:
7x-(3x+5)-8-(1/2(8x+20)-7x+5x)=0
Domain of the equation: 2(8x+20)-7x+5x)!=0
x∈R
We get rid of parentheses
7x-3x-(1/2(8x+20)-7x+5x)-5-8=0
We multiply all the terms by the denominator
7x*2(8x+20)-7x+5x)-3x*2(8x+20)-7x+5x)-(1-5*2(8x+20)-7x+5x)-8*2(8x+20)-7x+5x)=0
We add all the numbers together, and all the variables
-7x+7x*2(8x+20)+5x)-3x*2(8x+20)-7x+5x)-(1-5*2(8x+20)-7x+5x)-8*2(8x+20)-7x+5x)=0
Wy multiply elements
14x^2(8+5x)-7x-3x*2(8x+20)-7x+5x)-(1-5*2(8x+20)-7x+5x)-8*2(8x+20)-7x+5x)=0
We add all the numbers together, and all the variables
14x^2(5x+8)-7x-3x*2(8x+20)-7x+5x)-(1-5*2(8x+20)-7x+5x)-8*2(8x+20)-7x+5x)=0
We add all the numbers together, and all the variables
14x^2(5x+8)-21x-3x*2(8x+20)+5x)-(1-5*2(8x+20)+5x)-8*2(8x+20)-7x+5x)=0
Wy multiply elements
14x^2(5x+8)-6x^2(8+5x)-21x-(1-10x(8+5x)-8*2(8x+20)-7x+5x)=0
We calculate terms in parentheses: -(1-10x(8+5x)-8*2(8x+20)-7x+5x), so:
1-10x(8+5x)-8*2(8x+20)-7x+5x
determiningTheFunctionDomain -10x(8+5x)-8*2(8x+20)-7x+5x+1
We add all the numbers together, and all the variables
-10x(5x+8)-8*2(8x+20)-7x+5x+1
We add all the numbers together, and all the variables
-2x-10x(5x+8)-8*2(8x+20)+1
We multiply parentheses
-50x^2-2x-80x-8*2(8x+20)+1
Wy multiply elements
-50x^2-2x-80x-16x(8+1
We add all the numbers together, and all the variables
-50x^2-82x-16x(8+1
Back to the equation:
-(-50x^2-82x-16x(8+1)
We add all the numbers together, and all the variables
14x^2(5x+8)-6x^2(5x+8)-(-50x^2-82x-16x9-21x=0

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