7x-(3x+5)-8=1/2(x+20)-7x+5

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Solution for 7x-(3x+5)-8=1/2(x+20)-7x+5 equation: 



7x-(3x+5)-8=1/2(x+20)-7x+5

We move all terms to the left:

7x-(3x+5)-8-(1/2(x+20)-7x+5)=0



Domain of the equation: 2(x+20)-7x+5)!=0

x∈R



We get rid of parentheses

7x-3x-(1/2(x+20)-7x+5)-5-8=0

We multiply all the terms by the denominator


7x*2(x+20)-7x+5)-3x*2(x+20)-7x+5)-(1-5*2(x+20)-7x+5)-8*2(x+20)-7x+5)=0

We add all the numbers together, and all the variables

-7x+7x*2(x+20)+5)-3x*2(x+20)-7x+5)-(1-5*2(x+20)-7x+5)-8*2(x+20)-7x+5)=0

Wy multiply elements

14x^2(x+5)-7x-3x*2(x+20)-7x-5*2(x+20)-7x+5)-8*2(x+20)-7x+5)+5)-(1=0

We add all the numbers together, and all the variables

14x^2(x+5)-21x-3x*2(x+20)-5*2(x+20)+5)-8*2(x+20)-7x+5)+5)-(1=0

Wy multiply elements

14x^2(x+5)-6x^2(x-10x(x+5)-8*2(x+20)-7x+5)-21x+5)-(1=0

We add all the numbers together, and all the variables

14x^2(x+5)-6x^2(x-10x(x+5)-8*2(x+20)-7x+5)-21x=0

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