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7x-(4x-12)=-3(-x-4)
We move all terms to the left:
7x-(4x-12)-(-3(-x-4))=0
We add all the numbers together, and all the variables
7x-(4x-12)-(-3(-1x-4))=0
We get rid of parentheses
7x-4x-(-3(-1x-4))+12=0
We calculate terms in parentheses: -(-3(-1x-4)), so:We add all the numbers together, and all the variables
-3(-1x-4)
We multiply parentheses
3x+12
Back to the equation:
-(3x+12)
3x-(3x+12)+12=0
We get rid of parentheses
3x-3x-12+12=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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