7x-(4x-12)=40

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Solution for 7x-(4x-12)=40 equation: 



7x-(4x-12)=40

We move all terms to the left:

7x-(4x-12)-(40)=0

We get rid of parentheses

7x-4x+12-40=0

We add all the numbers together, and all the variables

3x-28=0

We move all terms containing x to the left, all other terms to the right

3x=28

x=28/3

x=9+1/3

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