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7x-(4x-3)(x-1)=x+12
We move all terms to the left:
7x-(4x-3)(x-1)-(x+12)=0
We get rid of parentheses
7x-(4x-3)(x-1)-x-12=0
We multiply parentheses ..
-(+4x^2-4x-3x+3)+7x-x-12=0
We add all the numbers together, and all the variables
-(+4x^2-4x-3x+3)+6x-12=0
We get rid of parentheses
-4x^2+4x+3x+6x-3-12=0
We add all the numbers together, and all the variables
-4x^2+13x-15=0
a = -4; b = 13; c = -15;
Δ = b2-4ac
Δ = 132-4·(-4)·(-15)
Δ = -71
Delta is less than zero, so there is no solution for the equation
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