7x-(5+(3x-2))=x-(4-5x)+(2x-1)

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Solution for 7x-(5+(3x-2))=x-(4-5x)+(2x-1) equation: 



7x-(5+(3x-2))=x-(4-5x)+(2x-1)

We move all terms to the left:

7x-(5+(3x-2))-(x-(4-5x)+(2x-1))=0

We add all the numbers together, and all the variables

7x-(5+(3x-2))-(x-(-5x+4)+(2x-1))=0



We calculate terms in parentheses: -(5+(3x-2)), so:

5+(3x-2)

determiningTheFunctionDomain
(3x-2)+5

We get rid of parentheses

3x-2+5

We add all the numbers together, and all the variables

3x+3

Back to the equation:

-(3x+3)





We calculate terms in parentheses: -(x-(-5x+4)+(2x-1)), so:

x-(-5x+4)+(2x-1)

We get rid of parentheses

x+5x+2x-4-1

We add all the numbers together, and all the variables

8x-5

Back to the equation:

-(8x-5)



We get rid of parentheses

7x-3x-8x-3+5=0

We add all the numbers together, and all the variables

-4x+2=0

We move all terms containing x to the left, all other terms to the right

-4x=-2

x=-2/-4

x=1/2

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