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7x-(5x-9)=3x-2(x+1)
We move all terms to the left:
7x-(5x-9)-(3x-2(x+1))=0
We get rid of parentheses
7x-5x-(3x-2(x+1))+9=0
We calculate terms in parentheses: -(3x-2(x+1)), so:We add all the numbers together, and all the variables
3x-2(x+1)
We multiply parentheses
3x-2x-2
We add all the numbers together, and all the variables
x-2
Back to the equation:
-(x-2)
2x-(x-2)+9=0
We get rid of parentheses
2x-x+2+9=0
We add all the numbers together, and all the variables
x+11=0
We move all terms containing x to the left, all other terms to the right
x=-11
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